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操作经理 可以看到操作部所有业务

lijunping 5 months ago
parent
commit
0422650f00

+ 2 - 2
blade-service/blade-los/src/main/java/org/springblade/los/business/sea/controller/BillsController.java

@@ -129,9 +129,9 @@ public class BillsController extends BladeController {
 			lambdaQueryWrapper.ge(Bills::getEta, bills.getEtaList().get(0));
 			lambdaQueryWrapper.le(Bills::getEta, bills.getEtaList().get(1));
 		}
-		if (!AuthUtil.getUserRole().contains("总部") && !AuthUtil.getUserRole().contains("admin")) {
+		if (!AuthUtil.getUserRole().contains("总部") && !AuthUtil.getUserRole().contains("admin")  ) {
 			lambdaQueryWrapper.eq(Bills::getBranchId, AuthUtil.getDeptId());
-			if (!AuthUtil.getUserRole().contains("secondaryAdmin") && !AuthUtil.getUserRole().contains("财务")) {
+			if (!AuthUtil.getUserRole().contains("secondaryAdmin") && !AuthUtil.getUserRole().contains("财务") && !AuthUtil.getUserRole().contains("操作经理")) {
 				lambdaQueryWrapper.and(i -> i.eq(AuthUtil.getUserRole().contains("业务员"), Bills::getSrcId, AuthUtil.getUserId()).or()
 					.eq(AuthUtil.getUserRole().contains("操作员"), Bills::getOperatorId, AuthUtil.getUserId()).or()
 					.eq(AuthUtil.getUserRole().contains("客服"), Bills::getCustomerServiceId, AuthUtil.getUserId()).or()